已知数据: Column1 Column2 Column3 Column4
A 10 am 1999-01-01 00:00:00.000
A 11 am 1999-01-02 00:00:00.000
B 12 bm 1999-01-03 00:00:00.000
B 13 bm 1999-01-04 00:00:00.000
C 14 cm 1999-01-05 00:00:00.000
C 15 cm 1999-01-06 00:00:00.000 要求得到数据:
Column1 Column2 Column3 Column4
A 11 am 1999-01-02 00:00:00.000
B 13 bm 1999-01-04 00:00:00.000
C 15 cm 1999-01-06 00:00:00.000 --数据装载 Create Table #T(Column1 varchar(10),Column2 int,Column3 varchar(10),Column4 datetime)
insert #T select 'A',10,'am','1999-1-1'
union all select 'A',11,'am','1999-1-2'
union all select 'B',12,'bm','1999-1-3'
union all select 'B',13,'bm','1999-1-4'
union all select 'C',14,'cm','1999-1-5'
union all select 'C',15,'cm','1999-1-6' --测试语句 方法1： select a.* from #T a
where (a.Column4) =
(select top 1 (Column4) from #T where Column1 = a.Column1 order by Column4 desc) --测试结果: Column1 Column2 Column3 Column4
---------- ----------- ---------- ------------------------------------------------------
A 11 am 1999-01-02 00:00:00.000
B 13 bm 1999-01-04 00:00:00.000
C 15 cm 1999-01-06 00:00:00.000 --测试语句 方法2:(最佳效率) select a.* from #T a join(
select Column1,Column4=max(Column4) from #T group by Column1
)b on a.Column1=b.Column1 and a.Column4=b.Column4
order by a.Column1 --测试结果 方法2: Column1 Column2 Column3 Column4
---------- ----------- ---------- ------------------------------------------------------
A 11 am 1999-01-02 00:00:00.000
B 13 bm 1999-01-04 00:00:00.000
C 15 cm 1999-01-06 00:00:00.000 
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