作者：未知 来源：月光软件站 加入时间：2005-2-28　月光软件站

Problem:

    In a Lotto I have ever played, one has to select 6 numbers from the set {1,2,...,49}. A popular strategy to play Lotto - although it doesn't increase your chance of winning - is to select a subset S containing k (k>6) of these 49 numbers, and then play several games with choosing numbers only from S. For example, for k=8 and S = {1,2,3,5,8,13,21,34} there are 28 possible games: [1,2,3,5,8,13], [1,2,3,5,8,21], [1,2,3,5,8,34], [1,2,3,5,13,21], ... [3,5,8,13,21,34].

    Your job is to write a program that reads in the number k and the set S and then prints all possible games choosing numbers only from S.

Intput:

Output:

    For each test case, print all possible games, each game on one line. The numbers of each game have to be sorted in ascending order and separated from each other by exactly one space. The games themselves have to be sorted lexicographically, that means sorted by the lowest number first, then by the second lowest and so on, as demonstrated in the sample output below. The test cases have to be separated from each other by exactly one blank line. Do not put a blank line after the last test case.



Sample Intput:

7 1 2 3 4 5 6 7
8 1 2 3 5 8 13 21 34
0



Sample Output:

1 2 3 4 5 6
1 2 3 4 5 7
1 2 3 4 6 7
1 2 3 5 6 7
1 2 4 5 6 7
1 3 4 5 6 7
2 3 4 5 6 7

1 2 3 5 8 13
1 2 3 5 8 21
1 2 3 5 8 34
1 2 3 5 13 21
1 2 3 5 13 34
1 2 3 5 21 34
1 2 3 8 13 21
1 2 3 8 13 34
1 2 3 8 21 34
1 2 3 13 21 34
1 2 5 8 13 21
1 2 5 8 13 34
1 2 5 8 21 34
1 2 5 13 21 34
1 2 8 13 21 34
1 3 5 8 13 21
1 3 5 8 13 34
1 3 5 8 21 34
1 3 5 13 21 34
1 3 8 13 21 34
1 5 8 13 21 34
2 3 5 8 13 21
2 3 5 8 13 34
2 3 5 8 21 34
2 3 5 13 21 34
2 3 8 13 21 34
2 5 8 13 21 34
3 5 8 13 21 34


Solution:

// 声明：本代码仅供学习之用，请不要作为个人的成绩提交。
// http://blog.csdn.net/mskia
// email: [email protected]

#include <iostream>
using namespace std;

int main( void ) {
    for ( int j = 0; ; ++j ) {
        int n;
        cin >> n;
        if ( n == 0 ) break;
       
        if ( j != 0 ) cout << endl;
   
        int* nums = new int[ n ];
        for ( int i = 0; i < n; ++i ) {
            cin >> nums[ i ];
        }
       
        for ( int i1 = 0; i1 < n; ++i1 ) {
        for ( int i2 = i1 + 1; i2 < n; ++i2 ) {
        for ( int i3 = i2 + 1; i3 < n; ++i3 ) {
        for ( int i4 = i3 + 1; i4 < n; ++i4 ) {
        for ( int i5 = i4 + 1; i5 < n; ++i5 ) {
        for ( int i6 = i5 + 1; i6 < n; ++i6 ) {
            cout << nums[ i1 ] << " "
                 << nums[ i2 ] << " "
                 << nums[ i3 ] << " "
                 << nums[ i4 ] << " "
                 << nums[ i5 ] << " "
                 << nums[ i6 ] << endl;
        }}}}}}
       

    }

    return 0;
}

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